Template:Formula Truncated circular cone

(Difference between revisions)

Latest revision as of 07:11, 16 June 2010

	Truncated circular cone
	$\rho=\frac{1}{2}\sqrt{4h^2+(d_2-d_1)^2}$ $V=\frac{\pi}{12}h(d_1^2+d_1d_2+d_2^2)$ $A=\frac{\pi}{2}\left [\frac{d_1^2+d_2^2}{2}+\rho(d_1+d_2)\right ]$

@@ Line 5: / Line 5: @@
 |-
 | [[Image:Truncated_circular_cone.gif]]
-| <math>V=\frac{\pi}{12}h(d_1^2+d_1d_2+d_2^2)</math>
+|<math>\rho=\frac{1}{2}\sqrt{4h^2+(d_2-d_1)^2}</math><br/>
+<math>V=\frac{\pi}{12}h(d_1^2+d_1d_2+d_2^2)</math><br/>
+<math>A=\frac{\pi}{2}\left [\frac{d_1^2+d_2^2}{2}+\rho(d_1+d_2)\right ] </math>
 |}